HDMI (High-Definition Multimedia Interface) is the first industry-supported, uncompressed, all-digital audio/video interface. HDMI provides an interface between any audio/video source, such as a set-top box, DVD player, and A/V receiver and an audio and/or video monitor, such as a digital television (DTV).

HDMI supports standard, enhanced, or high-definition video, plus multi-channel digital audio on a single cable. It transmits all ATSC HDTV standards and supports 8-channel digital audio, with bandwidth to spare to accommodate future enhancements and requirements.

Video Graphics Array (VGA) a graphics display system for PCs developed by IBM. VGA has become one of the de facto standards for PCs. In text mode, VGA systems provide a resolution of 720 by 400 pixels. In graphics mode, the resolution is either 640 by 480 (with 16 colors) or 320 by 200 (with 256 colors). The total palette of colors is 262,144.

Unlike earlier graphics standards for PCs — MDA, CGA, and EGA — VGA uses analog signals rather than digital signals. Consequently, a monitor designed for one of the older standards will not be able to use VGA.

Since its introduction in 1987, several other standards have been developed that offer greater resolution and more colors (see SVGA , 8514/A graphics standard, and XGA), but VGA remains the lowest common denominator. All PCs made today support VGA, and possibly some other more advanced standard.

All the prices for these headsets seem to have jumped astronomically since the introduction of the phone driving ban. Have tried all the usual places like ebay etc but still can't see anything cheap about their prices. Has anyone bought something similar from the myriad of hong kong shops listed?

Also has anyone had any problems with their headsets?

mozza

try http://www.yesasia.com

I bought mine from there… actually 2 headsets for my k800i…

I am wanting to draft up an SLA for the Direct Marketing Industry - does anyone have any samples ?

Service Level Agreement and SLA Template

The SLA Toolkit is a set of quality resources designed to help you create your own service level agreement as easily and quickly as possible.

http://www.service-level-agreement.net/

:> peace

I do not have an answering machine in my dorm room, so I don't have an answering service and people cannot leave me messages when I am not available. I'm pretty sure there is a way to retrieve messages just using the phone (entering numbers, voice mail, etc.) but I do not know how to do this. Help?

Thanks!

Talk to you phone service provider about adding voice mail.

How do you call from London to Mexico City?? What numbers must be dialed??
Thanks a lot!!
Regards.

http://www.timeanddate.com/worldclock/dialing.html
you enter where from and where you are calling to??
then it will give you calling codes..
International Dialing Codes - result
Dialing from London to Mexico City
Result, dial: 00 52 55 X
(If you are behind a switchboard you may have to dial '0' or '9' (or another number) to get an external line.)

How the number is composed
Number Comments
00 -00 is the international prefix used to dial somewhere outside of U.K..
52 -52 is the international code used to dial to Mexico.
55 -55 is the local area or city code used to dial to Mexico City.
X -X is the local number you wrote. Exchange X with your number

I've heard about a way to call Vietnam through internet-based-phoneline with fixed payment of 20 something bucks a month. Does anyone know about that?

My wife's in Vietnam and I also happen to be an Internet consultant who travels often to Vietnam.

Technically, you could use any Internet based phone service to make calls to a Vietnam phone. The more popular services are Yahoo Messenger and Skype. However, making calls through such services are usually more expensive than some of the phone card services available. I use services from Vietnam80, which has a tol charge of 9 cents/minute, where Skype has a tol charge of 15 cents/minute. On the other hand, it is cheaper to make calls from Vietnan to the U.S> by using an Internet phone card. Most charge less than 10 cents/minute.

The cheapest way to make calls to Vietnam is through an instant messaging service, such as Yahoo Messenger or Skype. Both are free of charge if the other party is also using teh same instant messenger service. I use Skype almost exclusively to keep in touch with my wife. I call her twice a day and have both audio and video (I can ehar and see her) with excellent quality.

If you want to get real technical, you can setup a VOIP phone and setup the phone in Vietnam with a U.S. phone number. You will pay toll only to where the phone number is supposed to originate, but the phone will ring and can be answered in Vietnam or anywhere where the VOIP phone is connected.

I hope this helps!

And if so, what sources can I use for information on how to do so and what retailers cell parts for laptops.

not really…

you pretty much have to pick components that are designed to fit in the case that you have, I don't know of any real forms, or standards in the laptop world…

if you are picking components ment to go in that case, then you can buy the exact computer that you are making from the factory, probably for less.

I just visited that newegg site, I didn't see any laptop components, except for some mobile processors. That only does you good when you have a laptop that you want a better processor in, nowhere near what you would need to do a whole laptop project.

department of service tax, detailed cloues service tax providers

Click on the link below for taxable services
http://www.allindiantaxes.com/service-tax-taxable-services.php
All details relating to service tax provisions are on the link below
http://www.allindiantaxes.com/service-tax.php

x^2 + xy + y^2 = n
Show that :
For every natural number n , the number of integral solutions (x,y) satisfying the equation is finite and a multiple of 6.
Plz. help.

It's actually not at all obvious. If n = 0, there's exactly one integral solution, (x,y) = (0,0), so I take it that by "natural number" you mean POSITIVE integer. If n is negative, there are no solutions.

So from here on, we'll assume n > 0.

First, let's show that there are only finitely many solutions.
Assume x^2 + xy + y^2 = n.
We'll show that x and y are in the range from -n to +n.
First, add xy to the equation.
x^2 + 2xy + y^2 = n + xy
(x + y)^2 = n + xy.
(x + y)^2 can't be negative, so n + xy >= 0
-n <= xy
Second, subtract 3xy from the equation.
x^2 - 2xy + y^2 = n - 3xy
(x - y)^2 = n - 3xy
(x - y)^2 can't be negative, so n - 3xy >= 0
3xy <= n
xy <= n/3 <= n
Putting together the two inequalities, we have
-n <= xy <= n
If x and y are both nonzero integers, then clearly they must both be in the range from -n to n.
If either x or y is zero, then going back to the original equation, we see that the other must be in the range from -n to n.
Thus, in any case, both x and y are in the range from -n to n.

There are only 2n+1 integers in the range from -n to n, and so there are only (2n+1)^2 pairs (x,y) with x and y both in this range. So there cannot be infinitely many solutions to the equation.
——————————
The other part claims the number of solutions is a multiple of 6.
For some values of n, like n = 2 or n = 5, the number of solutions is 0, which is divisible by 6.
From here on, we'll assume we have a value of n for which there is at least one solution.

Notice that if (a,b) is a solution then so are (b,a), (-a,-b), and (-b,-a).
Let's call these solutions (a,b), (b,a), (-a,-b), (-b,-a) an "equivalent group of solutions".
Normally there are 4 solutions in an equivalent group, but if a = b or a = -b then there will be just 2 solutions in the equivalent group.

The key to the proof is that if (x,y) = (a,b) is a solution, then (x,y) = (-a,a+b) also is a solution.
Proof: Assume (x,y) = (a,b) is a solution.
a^2 + ab + b^2 = n
Then if (x,y) = (-a,a+b), we get
x^2 + xy + y^2 = (-a)^2 + (-a)(a+b) + (a+b)^2
= a^2 - a^2 - ab + a^2 + 2ab + b^2
= a^2 + ab + b^2
= n
So (x,y) = (-a,a+b) is also a solution.

Notice that by a similar proof, (x,y) = (-b,a+b) also is a solution. Let's call (-a,a+b) and (-b,a+b) related solutions to (a,b).

Thus, if we have one solution (a,b), then we also have (-a,a+b) and (-b,a+b), and the equivalent group for each other of these. If we calculate the related solutions to any of these, we don't get any more new solutions.

So if we start with one solution (a,b), we can calculate the set of all related solutions and then the equivalent solutions for all these. This set will usually contain 12 solutions. But under certain special conditions, it will contain only 6 solutions The special conditions are any one of the following:
(1) a = b
(2) a = -b
(3) a = 0 or b = 0
(4) a = -2b or b = -2a

Since solutions to the equation come in sets of 6 or 12 related and equivalent solutions, the total number of solutions will be divisible by 6.

I have a B.A. and have also completed graduate coursework in IT and Business Management. The only problem is that I have somehow "wedged" myself into call center jobs over the past 4 years after graduation. I literally cannot stand the environment, but I have had tremendous difficulty getting into any other field. It usually goes like this… I end up taking a call center job, get burned out, quit the job (last instance was a year tenure) and then end up having to take ANOTHER call center job because I cannot get anything else!
I have plenty of talent, and would be suited for a variety of different work environments, but why the heck do I have such a hard time escaping the call center? I am concerned as my resume is going to start looking like a call center, job hopping joke, and I need help. This will not fly, the older I get.

I worked at Telemarketing Jobs for over 2 years, I know the feeling. I took a lower paying job at a temp agency so that I could get that off my resume. They helped me get a job doing something else.